Integrand size = 28, antiderivative size = 172 \[ \int \frac {(d+e x)^{9/2}}{\left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=\frac {105 e^3 (b d-a e) \sqrt {d+e x}}{8 b^5}+\frac {35 e^3 (d+e x)^{3/2}}{8 b^4}-\frac {21 e^2 (d+e x)^{5/2}}{8 b^3 (a+b x)}-\frac {3 e (d+e x)^{7/2}}{4 b^2 (a+b x)^2}-\frac {(d+e x)^{9/2}}{3 b (a+b x)^3}-\frac {105 e^3 (b d-a e)^{3/2} \text {arctanh}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{8 b^{11/2}} \]
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Time = 0.07 (sec) , antiderivative size = 172, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.179, Rules used = {27, 43, 52, 65, 214} \[ \int \frac {(d+e x)^{9/2}}{\left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=-\frac {105 e^3 (b d-a e)^{3/2} \text {arctanh}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{8 b^{11/2}}+\frac {105 e^3 \sqrt {d+e x} (b d-a e)}{8 b^5}-\frac {21 e^2 (d+e x)^{5/2}}{8 b^3 (a+b x)}-\frac {3 e (d+e x)^{7/2}}{4 b^2 (a+b x)^2}-\frac {(d+e x)^{9/2}}{3 b (a+b x)^3}+\frac {35 e^3 (d+e x)^{3/2}}{8 b^4} \]
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Rule 27
Rule 43
Rule 52
Rule 65
Rule 214
Rubi steps \begin{align*} \text {integral}& = \int \frac {(d+e x)^{9/2}}{(a+b x)^4} \, dx \\ & = -\frac {(d+e x)^{9/2}}{3 b (a+b x)^3}+\frac {(3 e) \int \frac {(d+e x)^{7/2}}{(a+b x)^3} \, dx}{2 b} \\ & = -\frac {3 e (d+e x)^{7/2}}{4 b^2 (a+b x)^2}-\frac {(d+e x)^{9/2}}{3 b (a+b x)^3}+\frac {\left (21 e^2\right ) \int \frac {(d+e x)^{5/2}}{(a+b x)^2} \, dx}{8 b^2} \\ & = -\frac {21 e^2 (d+e x)^{5/2}}{8 b^3 (a+b x)}-\frac {3 e (d+e x)^{7/2}}{4 b^2 (a+b x)^2}-\frac {(d+e x)^{9/2}}{3 b (a+b x)^3}+\frac {\left (105 e^3\right ) \int \frac {(d+e x)^{3/2}}{a+b x} \, dx}{16 b^3} \\ & = \frac {35 e^3 (d+e x)^{3/2}}{8 b^4}-\frac {21 e^2 (d+e x)^{5/2}}{8 b^3 (a+b x)}-\frac {3 e (d+e x)^{7/2}}{4 b^2 (a+b x)^2}-\frac {(d+e x)^{9/2}}{3 b (a+b x)^3}+\frac {\left (105 e^3 (b d-a e)\right ) \int \frac {\sqrt {d+e x}}{a+b x} \, dx}{16 b^4} \\ & = \frac {105 e^3 (b d-a e) \sqrt {d+e x}}{8 b^5}+\frac {35 e^3 (d+e x)^{3/2}}{8 b^4}-\frac {21 e^2 (d+e x)^{5/2}}{8 b^3 (a+b x)}-\frac {3 e (d+e x)^{7/2}}{4 b^2 (a+b x)^2}-\frac {(d+e x)^{9/2}}{3 b (a+b x)^3}+\frac {\left (105 e^3 (b d-a e)^2\right ) \int \frac {1}{(a+b x) \sqrt {d+e x}} \, dx}{16 b^5} \\ & = \frac {105 e^3 (b d-a e) \sqrt {d+e x}}{8 b^5}+\frac {35 e^3 (d+e x)^{3/2}}{8 b^4}-\frac {21 e^2 (d+e x)^{5/2}}{8 b^3 (a+b x)}-\frac {3 e (d+e x)^{7/2}}{4 b^2 (a+b x)^2}-\frac {(d+e x)^{9/2}}{3 b (a+b x)^3}+\frac {\left (105 e^2 (b d-a e)^2\right ) \text {Subst}\left (\int \frac {1}{a-\frac {b d}{e}+\frac {b x^2}{e}} \, dx,x,\sqrt {d+e x}\right )}{8 b^5} \\ & = \frac {105 e^3 (b d-a e) \sqrt {d+e x}}{8 b^5}+\frac {35 e^3 (d+e x)^{3/2}}{8 b^4}-\frac {21 e^2 (d+e x)^{5/2}}{8 b^3 (a+b x)}-\frac {3 e (d+e x)^{7/2}}{4 b^2 (a+b x)^2}-\frac {(d+e x)^{9/2}}{3 b (a+b x)^3}-\frac {105 e^3 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{8 b^{11/2}} \\ \end{align*}
Time = 0.82 (sec) , antiderivative size = 208, normalized size of antiderivative = 1.21 \[ \int \frac {(d+e x)^{9/2}}{\left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=-\frac {\sqrt {d+e x} \left (315 a^4 e^4-420 a^3 b e^3 (d-2 e x)+63 a^2 b^2 e^2 \left (d^2-18 d e x+11 e^2 x^2\right )+18 a b^3 e \left (d^3+10 d^2 e x-53 d e^2 x^2+8 e^3 x^3\right )+b^4 \left (8 d^4+50 d^3 e x+165 d^2 e^2 x^2-208 d e^3 x^3-16 e^4 x^4\right )\right )}{24 b^5 (a+b x)^3}+\frac {105 e^3 (-b d+a e)^{3/2} \arctan \left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {-b d+a e}}\right )}{8 b^{11/2}} \]
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Time = 2.68 (sec) , antiderivative size = 178, normalized size of antiderivative = 1.03
method | result | size |
risch | \(-\frac {2 e^{3} \left (-b e x +12 a e -13 b d \right ) \sqrt {e x +d}}{3 b^{5}}+\frac {\left (2 a^{2} e^{2}-4 a b d e +2 b^{2} d^{2}\right ) e^{3} \left (\frac {-\frac {55 b^{2} \left (e x +d \right )^{\frac {5}{2}}}{16}-\frac {35 \left (a e -b d \right ) b \left (e x +d \right )^{\frac {3}{2}}}{6}+\left (-\frac {41}{16} a^{2} e^{2}+\frac {41}{8} a b d e -\frac {41}{16} b^{2} d^{2}\right ) \sqrt {e x +d}}{\left (b \left (e x +d \right )+a e -b d \right )^{3}}+\frac {105 \arctan \left (\frac {b \sqrt {e x +d}}{\sqrt {\left (a e -b d \right ) b}}\right )}{16 \sqrt {\left (a e -b d \right ) b}}\right )}{b^{5}}\) | \(178\) |
pseudoelliptic | \(\frac {\frac {105 e^{3} \left (b x +a \right )^{3} \left (a e -b d \right )^{2} \arctan \left (\frac {b \sqrt {e x +d}}{\sqrt {\left (a e -b d \right ) b}}\right )}{8}-\frac {105 \sqrt {e x +d}\, \left (\left (-\frac {16}{315} e^{4} x^{4}-\frac {208}{315} d \,e^{3} x^{3}+\frac {11}{21} d^{2} e^{2} x^{2}+\frac {10}{63} d^{3} e x +\frac {8}{315} d^{4}\right ) b^{4}+\frac {2 a e \left (8 e^{3} x^{3}-53 d \,e^{2} x^{2}+10 d^{2} e x +d^{3}\right ) b^{3}}{35}+\frac {a^{2} e^{2} \left (11 x^{2} e^{2}-18 d e x +d^{2}\right ) b^{2}}{5}-\frac {4 a^{3} e^{3} \left (-2 e x +d \right ) b}{3}+e^{4} a^{4}\right ) \sqrt {\left (a e -b d \right ) b}}{8}}{b^{5} \left (b x +a \right )^{3} \sqrt {\left (a e -b d \right ) b}}\) | \(221\) |
derivativedivides | \(2 e^{3} \left (-\frac {-\frac {\left (e x +d \right )^{\frac {3}{2}} b}{3}+4 a e \sqrt {e x +d}-4 d b \sqrt {e x +d}}{b^{5}}+\frac {\frac {\left (-\frac {55}{16} a^{2} b^{2} e^{2}+\frac {55}{8} a \,b^{3} d e -\frac {55}{16} b^{4} d^{2}\right ) \left (e x +d \right )^{\frac {5}{2}}-\frac {35 b \left (a^{3} e^{3}-3 a^{2} b d \,e^{2}+3 a \,b^{2} d^{2} e -b^{3} d^{3}\right ) \left (e x +d \right )^{\frac {3}{2}}}{6}+\left (-\frac {41}{16} e^{4} a^{4}+\frac {41}{4} b \,e^{3} d \,a^{3}-\frac {123}{8} b^{2} e^{2} d^{2} a^{2}+\frac {41}{4} a \,b^{3} d^{3} e -\frac {41}{16} b^{4} d^{4}\right ) \sqrt {e x +d}}{\left (b \left (e x +d \right )+a e -b d \right )^{3}}+\frac {105 \left (a^{2} e^{2}-2 a b d e +b^{2} d^{2}\right ) \arctan \left (\frac {b \sqrt {e x +d}}{\sqrt {\left (a e -b d \right ) b}}\right )}{16 \sqrt {\left (a e -b d \right ) b}}}{b^{5}}\right )\) | \(267\) |
default | \(2 e^{3} \left (-\frac {-\frac {\left (e x +d \right )^{\frac {3}{2}} b}{3}+4 a e \sqrt {e x +d}-4 d b \sqrt {e x +d}}{b^{5}}+\frac {\frac {\left (-\frac {55}{16} a^{2} b^{2} e^{2}+\frac {55}{8} a \,b^{3} d e -\frac {55}{16} b^{4} d^{2}\right ) \left (e x +d \right )^{\frac {5}{2}}-\frac {35 b \left (a^{3} e^{3}-3 a^{2} b d \,e^{2}+3 a \,b^{2} d^{2} e -b^{3} d^{3}\right ) \left (e x +d \right )^{\frac {3}{2}}}{6}+\left (-\frac {41}{16} e^{4} a^{4}+\frac {41}{4} b \,e^{3} d \,a^{3}-\frac {123}{8} b^{2} e^{2} d^{2} a^{2}+\frac {41}{4} a \,b^{3} d^{3} e -\frac {41}{16} b^{4} d^{4}\right ) \sqrt {e x +d}}{\left (b \left (e x +d \right )+a e -b d \right )^{3}}+\frac {105 \left (a^{2} e^{2}-2 a b d e +b^{2} d^{2}\right ) \arctan \left (\frac {b \sqrt {e x +d}}{\sqrt {\left (a e -b d \right ) b}}\right )}{16 \sqrt {\left (a e -b d \right ) b}}}{b^{5}}\right )\) | \(267\) |
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Leaf count of result is larger than twice the leaf count of optimal. 360 vs. \(2 (140) = 280\).
Time = 0.31 (sec) , antiderivative size = 730, normalized size of antiderivative = 4.24 \[ \int \frac {(d+e x)^{9/2}}{\left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=\left [-\frac {315 \, {\left (a^{3} b d e^{3} - a^{4} e^{4} + {\left (b^{4} d e^{3} - a b^{3} e^{4}\right )} x^{3} + 3 \, {\left (a b^{3} d e^{3} - a^{2} b^{2} e^{4}\right )} x^{2} + 3 \, {\left (a^{2} b^{2} d e^{3} - a^{3} b e^{4}\right )} x\right )} \sqrt {\frac {b d - a e}{b}} \log \left (\frac {b e x + 2 \, b d - a e + 2 \, \sqrt {e x + d} b \sqrt {\frac {b d - a e}{b}}}{b x + a}\right ) - 2 \, {\left (16 \, b^{4} e^{4} x^{4} - 8 \, b^{4} d^{4} - 18 \, a b^{3} d^{3} e - 63 \, a^{2} b^{2} d^{2} e^{2} + 420 \, a^{3} b d e^{3} - 315 \, a^{4} e^{4} + 16 \, {\left (13 \, b^{4} d e^{3} - 9 \, a b^{3} e^{4}\right )} x^{3} - 3 \, {\left (55 \, b^{4} d^{2} e^{2} - 318 \, a b^{3} d e^{3} + 231 \, a^{2} b^{2} e^{4}\right )} x^{2} - 2 \, {\left (25 \, b^{4} d^{3} e + 90 \, a b^{3} d^{2} e^{2} - 567 \, a^{2} b^{2} d e^{3} + 420 \, a^{3} b e^{4}\right )} x\right )} \sqrt {e x + d}}{48 \, {\left (b^{8} x^{3} + 3 \, a b^{7} x^{2} + 3 \, a^{2} b^{6} x + a^{3} b^{5}\right )}}, -\frac {315 \, {\left (a^{3} b d e^{3} - a^{4} e^{4} + {\left (b^{4} d e^{3} - a b^{3} e^{4}\right )} x^{3} + 3 \, {\left (a b^{3} d e^{3} - a^{2} b^{2} e^{4}\right )} x^{2} + 3 \, {\left (a^{2} b^{2} d e^{3} - a^{3} b e^{4}\right )} x\right )} \sqrt {-\frac {b d - a e}{b}} \arctan \left (-\frac {\sqrt {e x + d} b \sqrt {-\frac {b d - a e}{b}}}{b d - a e}\right ) - {\left (16 \, b^{4} e^{4} x^{4} - 8 \, b^{4} d^{4} - 18 \, a b^{3} d^{3} e - 63 \, a^{2} b^{2} d^{2} e^{2} + 420 \, a^{3} b d e^{3} - 315 \, a^{4} e^{4} + 16 \, {\left (13 \, b^{4} d e^{3} - 9 \, a b^{3} e^{4}\right )} x^{3} - 3 \, {\left (55 \, b^{4} d^{2} e^{2} - 318 \, a b^{3} d e^{3} + 231 \, a^{2} b^{2} e^{4}\right )} x^{2} - 2 \, {\left (25 \, b^{4} d^{3} e + 90 \, a b^{3} d^{2} e^{2} - 567 \, a^{2} b^{2} d e^{3} + 420 \, a^{3} b e^{4}\right )} x\right )} \sqrt {e x + d}}{24 \, {\left (b^{8} x^{3} + 3 \, a b^{7} x^{2} + 3 \, a^{2} b^{6} x + a^{3} b^{5}\right )}}\right ] \]
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Timed out. \[ \int \frac {(d+e x)^{9/2}}{\left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=\text {Timed out} \]
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Exception generated. \[ \int \frac {(d+e x)^{9/2}}{\left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=\text {Exception raised: ValueError} \]
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Leaf count of result is larger than twice the leaf count of optimal. 358 vs. \(2 (140) = 280\).
Time = 0.27 (sec) , antiderivative size = 358, normalized size of antiderivative = 2.08 \[ \int \frac {(d+e x)^{9/2}}{\left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=\frac {105 \, {\left (b^{2} d^{2} e^{3} - 2 \, a b d e^{4} + a^{2} e^{5}\right )} \arctan \left (\frac {\sqrt {e x + d} b}{\sqrt {-b^{2} d + a b e}}\right )}{8 \, \sqrt {-b^{2} d + a b e} b^{5}} - \frac {165 \, {\left (e x + d\right )}^{\frac {5}{2}} b^{4} d^{2} e^{3} - 280 \, {\left (e x + d\right )}^{\frac {3}{2}} b^{4} d^{3} e^{3} + 123 \, \sqrt {e x + d} b^{4} d^{4} e^{3} - 330 \, {\left (e x + d\right )}^{\frac {5}{2}} a b^{3} d e^{4} + 840 \, {\left (e x + d\right )}^{\frac {3}{2}} a b^{3} d^{2} e^{4} - 492 \, \sqrt {e x + d} a b^{3} d^{3} e^{4} + 165 \, {\left (e x + d\right )}^{\frac {5}{2}} a^{2} b^{2} e^{5} - 840 \, {\left (e x + d\right )}^{\frac {3}{2}} a^{2} b^{2} d e^{5} + 738 \, \sqrt {e x + d} a^{2} b^{2} d^{2} e^{5} + 280 \, {\left (e x + d\right )}^{\frac {3}{2}} a^{3} b e^{6} - 492 \, \sqrt {e x + d} a^{3} b d e^{6} + 123 \, \sqrt {e x + d} a^{4} e^{7}}{24 \, {\left ({\left (e x + d\right )} b - b d + a e\right )}^{3} b^{5}} + \frac {2 \, {\left ({\left (e x + d\right )}^{\frac {3}{2}} b^{8} e^{3} + 12 \, \sqrt {e x + d} b^{8} d e^{3} - 12 \, \sqrt {e x + d} a b^{7} e^{4}\right )}}{3 \, b^{12}} \]
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Time = 9.49 (sec) , antiderivative size = 388, normalized size of antiderivative = 2.26 \[ \int \frac {(d+e x)^{9/2}}{\left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=\frac {2\,e^3\,{\left (d+e\,x\right )}^{3/2}}{3\,b^4}-\frac {{\left (d+e\,x\right )}^{5/2}\,\left (\frac {55\,a^2\,b^2\,e^5}{8}-\frac {55\,a\,b^3\,d\,e^4}{4}+\frac {55\,b^4\,d^2\,e^3}{8}\right )+{\left (d+e\,x\right )}^{3/2}\,\left (\frac {35\,a^3\,b\,e^6}{3}-35\,a^2\,b^2\,d\,e^5+35\,a\,b^3\,d^2\,e^4-\frac {35\,b^4\,d^3\,e^3}{3}\right )+\sqrt {d+e\,x}\,\left (\frac {41\,a^4\,e^7}{8}-\frac {41\,a^3\,b\,d\,e^6}{2}+\frac {123\,a^2\,b^2\,d^2\,e^5}{4}-\frac {41\,a\,b^3\,d^3\,e^4}{2}+\frac {41\,b^4\,d^4\,e^3}{8}\right )}{b^8\,{\left (d+e\,x\right )}^3-\left (3\,b^8\,d-3\,a\,b^7\,e\right )\,{\left (d+e\,x\right )}^2+\left (d+e\,x\right )\,\left (3\,a^2\,b^6\,e^2-6\,a\,b^7\,d\,e+3\,b^8\,d^2\right )-b^8\,d^3+a^3\,b^5\,e^3-3\,a^2\,b^6\,d\,e^2+3\,a\,b^7\,d^2\,e}+\frac {2\,e^3\,\left (4\,b^4\,d-4\,a\,b^3\,e\right )\,\sqrt {d+e\,x}}{b^8}+\frac {105\,e^3\,\mathrm {atan}\left (\frac {\sqrt {b}\,e^3\,{\left (a\,e-b\,d\right )}^{3/2}\,\sqrt {d+e\,x}}{a^2\,e^5-2\,a\,b\,d\,e^4+b^2\,d^2\,e^3}\right )\,{\left (a\,e-b\,d\right )}^{3/2}}{8\,b^{11/2}} \]
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